
exp(-
/
)


exp(-
/
)
=
2
(log Z)/
.
Then
Z = 1 + exp(-
/
)
and U =
e-
/
.
/Z =
/
(e
/
+ 1)
/2 and the upper state has an
energy of +
/2.
Then
Z = exp(+
/2
)
+ exp(-
/2
)
= 2 cosh(
/2
)
and U = -(
/2)
tanh(
/2
).
(
U/
)V
for which we obtain in each of the two cases
CV =
(
/
)2
.
e
/
/ (e
/
+ 1)2.
LIMITING CASES:
0:
/
1 so
e
/
1, leaving
U
e-
/
0 and
CV
(
/
)2
e-
/
0 as well. (The exponential always grows or shrinks
faster than any power law.)
:
/
0 so
e
/
1
/
, giving
U
/(2+
/
)
/2
(i.e. no preference for either state) and
CV
(
/
)2
(1+
/
) /
(2+
/
)2
½
(
/
)2
0.
(Once both states are equally populated, there is no place to put any more energy
on a statistical basis.)