THE UNIVERSITY OF BRITISH COLUMBIA

PHYSICS 455

Lecture # 6 :

Fri. 17 Jan. 1997

Two-State Systems


I. Recapitulate:

II. Simplest Possible Case: TWO-STATE SYSTEM

  1. Let the energy of the lower state be zero and that of the upper state be .

    Then Z = 1 + exp(-/)

    and U = e-/. /Z = / (e/ + 1)

  2. Alternatively, we can set the zero of energy halfway in between the two states (as in the case of a spin-½ particle in a magnetic field), so that the lower state has an energy of -/2 and the upper state has an energy of +/2.

    Then Z = exp(+/2) + exp(-/2) = 2 cosh(/2)

    and U = -(/2) tanh(/2).

These results look different; but no physical observable can depend upon where we choose the zero of energy. Such an observable is the heat capacity at constant volume, CV (U/)V for which we obtain in each of the two cases

CV = (/)2 . e/ / (e/ + 1)2.

[You may want to check this for yourself.] The peak in CV is called the Schottky anomaly.

LIMITING CASES:


Last modified: Mon Feb 3 07:38:55 PST